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R语言矩阵广义逆(Moore-Penrose)实例

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发表于 2011-3-3 22:51:48 | 显示全部楼层 |阅读模式
矩阵广义逆(Moore-Penrose)
n×m矩阵A+称为m×n矩阵A的Moore-Penrose逆,如果它满足下列条件:
① A A+A=A;②A+A A+= A+;③(A A+)H=A A+;④(A+A)H= A+A
在R的MASS包中的函数ginv()可计算矩阵A的Moore-Penrose逆,例如:
library(“MASS”)
> A
[,1] [,2] [,3] [,4]
[1,] 1 5 9 13
[2,] 2 6 10 14
[3,] 3 7 11 15
[4,] 4 8 12 16
> ginv(A)
[,1] [,2] [,3] [,4]
[1,] -0.285 -0.1075 0.07 0.2475
[2,] -0.145 -0.0525 0.04 0.1325
[3,] -0.005 0.0025 0.01 0.0175
[4,] 0.135 0.0575 -0.02 -0.0975
验证性质1:
> A%*%ginv(A)%*%A
[,1] [,2] [,3] [,4]
[1,] 1 5 9 13
[2,] 2 6 10 14
[3,] 3 7 11 15
[4,] 4 8 12 16
验证性质2:
> ginv(A)%*%A%*%ginv(A)
[,1] [,2] [,3] [,4]
[1,] -0.285 -0.1075 0.07 0.2475
[2,] -0.145 -0.0525 0.04 0.1325
[3,] -0.005 0.0025 0.01 0.0175
[4,] 0.135 0.0575 -0.02 -0.0975
验证性质3:
> t(A%*%ginv(A))
[,1] [,2] [,3] [,4]
[1,] 0.7 0.4 0.1 -0.2
[2,] 0.4 0.3 0.2 0.1
[3,] 0.1 0.2 0.3 0.4
[4,] -0.2 0.1 0.4 0.7
> A%*%ginv(A)
[,1] [,2] [,3] [,4]
[1,] 0.7 0.4 0.1 -0.2
[2,] 0.4 0.3 0.2 0.1
[3,] 0.1 0.2 0.3 0.4
[4,] -0.2 0.1 0.4 0.7
验证性质4:
> t(ginv(A)%*%A)
[,1] [,2] [,3] [,4]
[1,] 0.7 0.4 0.1 -0.2
[2,] 0.4 0.3 0.2 0.1
[3,] 0.1 0.2 0.3 0.4
[4,] -0.2 0.1 0.4 0.7
> ginv(A)%*%A
[,1] [,2] [,3] [,4]
[1,] 0.7 0.4 0.1 -0.2
[2,] 0.4 0.3 0.2 0.1
[3,] 0.1 0.2 0.3 0.4
[4,] -0.2 0.1 0.4 0.7
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