overlap.feat(rphast)
overlap.feat()所属R语言包：rphast
Feature overlap...
功能重叠...
译者：生物统计家园网 机器人LoveR
描述----------Description----------
Feature overlap
功能重叠
用法----------Usage----------
get.fragments=FALSE, pointer.only=FALSE)
参数----------Arguments----------
参数：x
An object of type feat containing features to select
类型feat，其中包含选择的对象
参数：filter
An object of type feat which determines which elements of x to select
feat这类型的对象，决定选择哪些元素的x
参数：numbase
The number of bases of overlap between x and filter required to choose a record. Use NULL to ignore (but then min.percent must be defined)
需要选择一个记录的数目x和过滤器之间的重叠的碱基。使用NULL忽略（但，然后min.percent必须定义）
参数：min.percent
The minimum percent that a record must overlap with the combined records in filter in order to be chosen
记录必须重叠，以便在过滤器的组合的记录，以被选择的最小％
参数：overlapping
If FALSE, choose records with less than numbase overlapping bases, and less than min.percent fraction overlap if min.percent is not NULL
如果FALSE，选择记录小于numbase重叠碱基，和小于min.percent馏分重叠，如果min.percent不是NULL
参数：get.fragments
If FALSE, entire records are selected from x based on whether they meet selection criteria. If TRUE, return only the fragments of x that overlap with filter. In this case, the same fragments may be output multiple times, if they are selected by multiple entries in filter. numbase and min.percent apply in either case.
如果FALSE，整个记录的选择是否符合选择标准的基础上，从X。如果TRUE，只返回x的片段重叠过滤器。在这种情况下，相同的片段可以是多次输出，如果他们是在过滤器中的多个条目中选择。 numbase和min.percent申请在上述任何一种情况下。
参数：pointer.only
If TRUE, the return object will only be a pointer to an object stored in C (useful for very large features; advanced use only).
如果TRUE，返回的对象只能是一个指针，指向一个对象存储在C（适用于非常大的特点，先进的使用）。
Details
详细信息----------Details----------
Creates a features object containing all the features from one set which overlap
创建一个功能对象，包含所有的功能从一组重叠
值----------Value----------
an object of type feat containing the selected entries from x.
类型的对象feat包含从x选定的条目。
注意----------Note----------
If either x or filter are feature objects stored as a pointer to C memory, then this function may reorder the elements in these objects, but leave them
如果x或过滤器的功能对象存储为一个指针，指向C内存，那么这个函数可能在这些对象中的元素重新排序，但让他们
（作者）----------Author(s)----------
Melissa J. Hubisz
实例----------Examples----------
feat1 <- feat(seqname=c(rep("chr1", 3), rep("chr2", 2)),
start=c(1, 5, 100, 10, 20),
end=c(7, 10, 105, 15, 30))
feat2 <- feat(seqname=c("chr1","chr2"),
start=c(1,1),
end=c(5,10))
overlap.feat(feat1, feat1)
overlap.feat(feat1, feat2, min.percent=0.25)
overlap.feat(feat1, feat2, min.percent=0.25, overlapping=FALSE)
overlap.feat(feat1, feat2, get.fragments=TRUE)
overlap.feat(feat1, feat2, get.fragments=TRUE)
rm(feat1, feat2)
转载请注明:出自 生物统计家园网(http://www.biostatistic.net)。
注：
注1：为了方便大家学习，本文档为生物统计家园网机器人LoveR翻译而成，仅供个人R语言学习参考使用，生物统计家园保留版权。
注2：由于是机器人自动翻译，难免有不准确之处，使用时仔细对照中、英文内容进行反复理解，可以帮助R语言的学习。
注3：如遇到不准确之处，请在本贴的后面进行回帖，我们会逐渐进行修订。
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发表于 2012-9-28 00:01:41
